Distance from Altus to La Puebla del Rio
The shortest distance (air line) between Altus and La Puebla del Rio is 4,982.47 mi (8,018.52 km).
How far is Altus from La Puebla del Rio
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 19:18 (30.08.2025)
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 02:18 (31.08.2025)
The calculated flying distance from La Puebla del Rio to La Puebla del Rio is 4,982.47 miles which is equal to 8,018.52 km.
Altus, Oklahoma, United States
Related Distances from Altus
La Puebla del Rio, Sevilla, Spain