Distance from Altus to Diekirch
The shortest distance (air line) between Altus and Diekirch is 5,039.48 mi (8,110.27 km).
How far is Altus from Diekirch
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 21:22 (14.08.2025)
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 04:22 (15.08.2025)
The calculated flying distance from Diekirch to Diekirch is 5,039.48 miles which is equal to 8,110.27 km.
Altus, Oklahoma, United States
Related Distances from Altus
Diekirch, Luxembourg, Luxembourg
Related Distances to Diekirch
Cities | Distance |
---|---|
Vianden to Diekirch | 5.06 mi (8.14 km) |
Mersch to Diekirch | 8.54 mi (13.75 km) |
Wiltz to Diekirch | 12.05 mi (19.39 km) |
Echternach to Diekirch | 12.43 mi (20.01 km) |
Clervaux to Diekirch | 13.71 mi (22.07 km) |
Redange-sur-Attert to Diekirch | 13.88 mi (22.33 km) |
Capellen to Diekirch | 17.16 mi (27.62 km) |
Luxembourg to Diekirch | 17.75 mi (28.57 km) |
Grevenmacher to Diekirch | 18.15 mi (29.22 km) |
Remich to Diekirch | 24.25 mi (39.03 km) |
Differdange to Diekirch | 26.67 mi (42.93 km) |
Dudelange to Diekirch | 26.79 mi (43.11 km) |
Esch-sur-Alzette to Diekirch | 26.83 mi (43.18 km) |