Distance from Alexandroupoli to Diepenbeek
The shortest distance (air line) between Alexandroupoli and Diepenbeek is 1,197.78 mi (1,927.64 km).
How far is Alexandroupoli from Diepenbeek
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 12:41 (30.05.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 11:41 (30.05.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 1,197.78 miles which is equal to 1,927.64 km.
Related Distances from Alexandroupoli
Diepenbeek, Arr. Hasselt, Belgium