Distance from Aleksandrow Kujawski to Sarrebourg
The shortest distance (air line) between Aleksandrow Kujawski and Sarrebourg is 582.28 mi (937.09 km).
How far is Aleksandrow Kujawski from Sarrebourg
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 08:59 (03.06.2025)
Sarrebourg is located in Moselle, France within 48° 44' 4.92" N 7° 3' 14.04" E (48.7347, 7.0539) coordinates. The local time in Sarrebourg is 08:59 (03.06.2025)
The calculated flying distance from Sarrebourg to Sarrebourg is 582.28 miles which is equal to 937.09 km.
Aleksandrow Kujawski, Włocławski, Poland