Distance from Aleksandrovac to Vetraz-Monthoux
The shortest distance (air line) between Aleksandrovac and Vetraz-Monthoux is 747.93 mi (1,203.68 km).
How far is Aleksandrovac from Vetraz-Monthoux
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 11:32 (12.10.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 11:32 (12.10.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 747.93 miles which is equal to 1,203.68 km.
Aleksandrovac, Rasinska oblast, Serbia
Related Distances from Aleksandrovac
Vetraz-Monthoux, Haute-Savoie, France