Distance from Aleksandrovac to Port-de-Bouc
The shortest distance (air line) between Aleksandrovac and Port-de-Bouc is 804.73 mi (1,295.09 km).
How far is Aleksandrovac from Port-de-Bouc
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 03:40 (12.10.2025)
Port-de-Bouc is located in Bouches-du-Rhône, France within 43° 24' 18" N 4° 59' 18.96" E (43.4050, 4.9886) coordinates. The local time in Port-de-Bouc is 03:40 (12.10.2025)
The calculated flying distance from Port-de-Bouc to Port-de-Bouc is 804.73 miles which is equal to 1,295.09 km.
Aleksandrovac, Rasinska oblast, Serbia
Related Distances from Aleksandrovac
Port-de-Bouc, Bouches-du-Rhône, France