Distance from Aleksandrovac to Chateauroux
The shortest distance (air line) between Aleksandrovac and Chateauroux is 969.00 mi (1,559.46 km).
How far is Aleksandrovac from Chateauroux
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 05:09 (10.10.2025)
Chateauroux is located in Indre, France within 46° 48' 37.08" N 1° 41' 27.96" E (46.8103, 1.6911) coordinates. The local time in Chateauroux is 05:09 (10.10.2025)
The calculated flying distance from Chateauroux to Chateauroux is 969.00 miles which is equal to 1,559.46 km.
Aleksandrovac, Rasinska oblast, Serbia