Distance from Albany to Bad Sassendorf
The shortest distance (air line) between Albany and Bad Sassendorf is 3,696.26 mi (5,948.56 km).
How far is Albany from Bad Sassendorf
Albany is located in New York, United States within 42° 39' 59.04" N -74° 12' 4.68" W (42.6664, -73.7987) coordinates. The local time in Albany is 06:47 (08.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 12:47 (08.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 3,696.26 miles which is equal to 5,948.56 km.
Albany, New York, United States
Related Distances from Albany
Bad Sassendorf, Soest, Germany