Distance from Alachua to Savigny-le-Temple
The shortest distance (air line) between Alachua and Savigny-le-Temple is 4,494.54 mi (7,233.26 km).
How far is Alachua from Savigny-le-Temple
Alachua is located in Florida, United States within 29° 46' 40.44" N -83° 31' 0.48" W (29.7779, -82.4832) coordinates. The local time in Alachua is 03:59 (29.07.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 09:59 (29.07.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 4,494.54 miles which is equal to 7,233.26 km.
Alachua, Florida, United States
Related Distances from Alachua
Savigny-le-Temple, Seine-et-Marne, France