Distance from Agia Paraskevi to Aleksandrow Kujawski
The shortest distance (air line) between Agia Paraskevi and Aleksandrow Kujawski is 1,056.02 mi (1,699.51 km).
How far is Agia Paraskevi from Aleksandrow Kujawski
Agia Paraskevi is located in Voreios Tomeas Athinon, Greece within 38° 0' 42.12" N 23° 49' 12" E (38.0117, 23.8200) coordinates. The local time in Agia Paraskevi is 06:05 (17.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 05:05 (17.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 1,056.02 miles which is equal to 1,699.51 km.
Agia Paraskevi, Voreios Tomeas Athinon, Greece
Related Distances from Agia Paraskevi
Aleksandrow Kujawski, Włocławski, Poland